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https://gerrit.wikimedia.org/r/mediawiki/extensions/VisualEditor
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6d999d8504
Also fix some comment & whitespace inconsistencies. Change-Id: I71717643678445590820e174e6ed2e5ac58103c2
92 lines
2.4 KiB
JavaScript
92 lines
2.4 KiB
JavaScript
/*!
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* UnicodeJS Graphemebreak module
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*
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* Implementation of grapheme cluster boundary detection, based on
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* Unicode UAX #29 Default Grapheme Cluster Boundary Specification; see
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* http://www.unicode.org/reports/tr29/#Default_Grapheme_Cluster_Table
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*
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* @copyright 2013 UnicodeJS team and others; see AUTHORS.txt
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* @license The MIT License (MIT); see LICENSE.txt
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*/
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( function () {
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var property, disjunction, graphemeBreakRegexp,
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properties = unicodeJS.graphemebreakproperties,
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// Single unicode character (either a UTF-16 code unit or a surrogate pair)
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oneCharacter = '[^\\ud800-\\udfff]|[\\ud800-\\udbff][\\udc00-\\udfff]',
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/**
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* @class unicodeJS.graphemebreak
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* @singleton
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*/
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graphemebreak = unicodeJS.graphemebreak = {},
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patterns = {};
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// build regexes
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for ( property in properties ) {
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patterns[property] = unicodeJS.charRangeArrayRegexp( properties[property] );
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}
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// build disjunction for grapheme cluster split
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// See http://www.unicode.org/reports/tr29/ at "Grapheme Cluster Boundary Rules"
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disjunction = [
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// GB1 and GB2 are trivially satisfied
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// GB3
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'\\r\\n',
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// GB4, GB5
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patterns.Control,
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// GB6, GB7, GB8
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'(?:' + patterns.L + ')*' +
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'(?:' + patterns.V + ')+' +
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'(?:' + patterns.T + ')*',
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'(?:' + patterns.L + ')*' +
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'(?:' + patterns.LV + ')' +
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'(?:' + patterns.V + ')*' +
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'(?:' + patterns.T + ')*',
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'(?:' + patterns.L + ')*' +
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'(?:' + patterns.LVT + ')' +
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'(?:' + patterns.T + ')*',
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'(?:' + patterns.L + ')+',
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'(?:' + patterns.T + ')+',
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// GB8a
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/*jshint camelcase:false */
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'(?:' + patterns.Regional_Indicator + ')+',
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/*jshint camelcase:true */
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// GB9, GB9a
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// (GB9b: As of Unicode 6.2, no characters are "Prepend")
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// TODO: this will break if the extended thing is not oneCharacter
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// e.g. hangul jamo L+V+T. Does it matter?
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'(?:' + oneCharacter + ')' +
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'(?:' + patterns.Extend + '|' +
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patterns.SpacingMark + ')+',
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// GB10 (taking care not to split surrogates)
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oneCharacter
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];
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graphemeBreakRegexp = new RegExp( '(' + disjunction.join( '|' ) + ')' );
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/**
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* Split a string into grapheme clusters.
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*
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* @param {string} text Text to split
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* @returns {string[]} Array of clusters
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*/
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graphemebreak.splitClusters = function ( text ) {
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var i, parts, length, clusters = [];
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parts = text.split( graphemeBreakRegexp );
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for ( i = 0, length = parts.length; i < length; i++ ) {
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if ( parts[i] !== '' ) {
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clusters.push( parts[i] );
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}
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}
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return clusters;
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};
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}() );
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