2012-08-24 02:06:36 +00:00
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/**
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* VisualEditor OrderedHashSet class.
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*
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* @copyright 2011-2012 VisualEditor Team and others; see AUTHORS.txt
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* @license The MIT License (MIT); see LICENSE.txt
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*/
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/**
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* Ordered set of objects. Objects are treated as equal if their hashes are equal. This means that
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* you can't add two objects with the same hash, and it also means that you can search for one
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* object and get a different one back that has the same hash.
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*
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* The second parameter to this constructor can be an array of objects, or an existing
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* ve.OrderedHashSet object. In both cases, the new Set will be a shallow copy: object references
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* to the individual objects will be maintained, but references to the original array or
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* ve.OrderedHashSet will not be.
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*
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* @class
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* @abstract
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* @constructor
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* @param {Function} hash Hash function
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* @param {Array|ve.OrderedHashSet} [items] Items to populate this set with
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*/
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2012-10-08 04:12:50 +00:00
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ve.OrderedHashSet = function VeOrderedHashSet( hash, items ) {
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2012-08-24 02:06:36 +00:00
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var i;
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this.hash = hash;
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// Array of object references
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this.arr = [];
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// Object mapping object hashes to object references
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this.map = {};
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// HACK HACK HACK
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// We should fix our inheritance so instanceof works
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if ( items instanceof ve.OrderedHashSet || items instanceof ve.AnnotationSet ) {
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this.map = ve.extendObject( {}, items.map );
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this.arr = items.arr.slice( 0 );
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} else if ( ve.isArray( items ) && items.length > 0 ) {
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this.arr = items.slice( 0 );
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for ( i = 0; i < this.arr.length; i++ ) {
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this.map[this.hash( this.arr[i] )] = this.arr[i];
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}
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}
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};
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/* Methods */
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/**
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* Create a clone of this set, with the same hash function and the same contents.
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* @returns {ve.OrderedHashSet}
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*/
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ve.OrderedHashSet.prototype.clone = function () {
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return new ve.OrderedHashSet( this.hash, this );
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};
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/**
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* Get a value or all values from the set.
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*
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* set.get( 5 ) returns the object at index 5, set.get() returns an array with all objects in
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* the entire set.
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*
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* @param {Number} [index] If set, only get the element at this index
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* @returns {Array|Object|undefined} The object at index, or an array of all objects in the set
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*/
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ve.OrderedHashSet.prototype.get = function ( index ) {
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if ( index !== undefined ) {
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return this.arr[index];
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} else {
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return this.arr.slice( 0 );
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}
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};
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/**
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* @returns {Number} The number of objects in the set
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*/
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ve.OrderedHashSet.prototype.getLength = function () {
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return this.arr.length;
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};
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/**
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* @returns {Boolean} True if the set is empty, false otherwise
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*/
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ve.OrderedHashSet.prototype.isEmpty = function () {
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return this.arr.length === 0;
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};
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/**
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* Check whether a given value occurs in the set. Values are compared by hash.
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*
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* @returns {Boolean} True if there is an object in the set with the same hash as value, false otherwise
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*/
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ve.OrderedHashSet.prototype.contains = function ( value ) {
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return this.hash( value ) in this.map;
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};
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/**
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* Check whether this set contains any of the values in another set.
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*
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* @param {ve.OrderedHashSet} set Set to compare this set with
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* @returns {Boolean} True if there is at least one value in set that is also in this set, false otherwise
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*/
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ve.OrderedHashSet.prototype.containsAnyOf = function ( set ) {
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var key;
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for ( key in set.map ) {
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if ( key in this.map ) {
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return true;
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}
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}
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return false;
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};
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/**
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* Check whether this set contains all of the values in another set.
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*
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* @param {ve.OrderedHashSet} set Set to compare this set with
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* @returns {Boolean} True if all values in set are also in this set, false otherwise
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*/
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ve.OrderedHashSet.prototype.containsAllOf = function ( set ) {
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var key;
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for ( key in set.map ) {
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if ( !( key in this.map ) ) {
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return false;
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}
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}
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return true;
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};
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/**
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* Get the index of a given value in this set.
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*
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* @param {Object} value Value to search for
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* @returns {Number} Index of value in this set, or -1 if value is not in this set.
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*/
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ve.OrderedHashSet.prototype.indexOf = function ( value ) {
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var hash = this.hash( value );
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if ( hash in this.map ) {
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return ve.indexOf( this.map[hash], this.arr );
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} else {
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return -1;
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}
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};
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/**
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* Filter this set by a given property. This returns a new set with all values in this set for
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* which value.property matches filter (if filter is a RegExp) or is equal to filter,
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*
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* @param {String} property Property to check
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* @param {Mixed|RegExp} filter Regular expression or value to filter for
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* @param {Boolean} [returnBool] For internal use only
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* @returns {ve.OrderedHashSet} New set containing only the matching values
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*/
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ve.OrderedHashSet.prototype.filter = function ( property, filter, returnBool ) {
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var i, result;
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if ( !returnBool ) {
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2012-09-26 19:10:37 +00:00
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// TODO: Consider alternative ways to instantiate a new set of the same type as the subclass
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2012-08-24 02:06:36 +00:00
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result = this.clone();
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2012-09-26 19:10:37 +00:00
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// TODO: Should we be returning this on all methods that modify the original? Might help
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// with chainability, but perhaps it's also confusing because most chainable methods return
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// a new hash set.
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result.removeAll();
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2012-08-24 02:06:36 +00:00
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}
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for ( i = 0; i < this.arr.length; i++ ) {
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if (
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2012-09-26 19:10:37 +00:00
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( filter instanceof RegExp && filter.test( this.arr[i][property] ) ) ||
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( typeof filter === 'string' && this.arr[i][property] === filter )
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2012-08-24 02:06:36 +00:00
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) {
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if ( returnBool ) {
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return true;
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} else {
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result.push( this.arr[i] );
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}
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}
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}
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return returnBool ? false : result;
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};
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/**
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* Check if this set contains at least one value where a given property matches a given filter.
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*
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* This is equivalent to (but more efficient than) !this.filter( .. ).isEmpty()
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* @see ve.OrderedHashSet.prototype.filter
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*
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* @param {String} property
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* @param {Mixed|RegExp} filter
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* @returns {Boolean} True if at least one value matches, false otherwise
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*/
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ve.OrderedHashSet.prototype.containsMatching = function ( property, filter ) {
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return this.filter( property, filter, true );
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};
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/**
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* Add a value to this set. If the value is already present in this set, nothing happens.
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*
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* The value will be inserted before the value that is currently at the given index. If index is
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* negative, it will be counted from the end (i.e. index -1 is the last item, -2 the second-to-last,
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* etc.). If index is out of bounds, the value will be added to the end of the set.
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*
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* @param {Object} value Value to add
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* @param {Number} index Index to add the value at
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*/
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ve.OrderedHashSet.prototype.add = function ( value, index ) {
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var hash;
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if ( index < 0 ) {
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index = this.arr.length + index;
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}
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if ( index >= this.arr.length ) {
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this.push( value );
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return;
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}
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hash = this.hash( value );
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if ( !( hash in this.map ) ) {
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this.arr.splice( index, 0, value );
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this.map[hash] = value;
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}
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};
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/**
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* Add all values in the given set to the end of this set. Values from the other set that are
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* already in this set will not be added again.
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* @param {ve.OrderedHashSet} set Set to add to this set
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*/
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ve.OrderedHashSet.prototype.addSet = function ( set ) {
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var i;
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for ( i = 0; i < set.arr.length; i++ ) {
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this.push( set.arr[i] );
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}
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};
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/**
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* Add a value at the end of this set. If the value is already present in this set, nothing happens.
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* @param {Object} value Value to add
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*/
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ve.OrderedHashSet.prototype.push = function ( value ) {
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var hash = this.hash( value );
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if ( !( hash in this.map ) ) {
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this.arr.push( value );
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this.map[hash] = value;
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}
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};
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/**
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* Remove the value at a given index
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* @param {Number} index Index to remove item at. If negative, this counts from the end, see add()
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* @throws {Error} 'Index out of bounds'
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*/
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ve.OrderedHashSet.prototype.removeAt = function ( index ) {
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if ( index < 0 ) {
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index = this.arr.length + index;
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}
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if ( index >= this.arr.length ) {
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throw new Error( 'Index out of bounds' );
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}
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delete this.map[this.hash( this.arr[index] )];
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this.arr.splice( index, 1 );
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};
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/**
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* Remove a given value from the set. If the value isn't in the set, nothing happens.
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* @param {Object} value Value to remove
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*/
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ve.OrderedHashSet.prototype.remove = function ( value ) {
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var index, hash = this.hash( value );
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if ( hash in this.map ) {
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index = ve.indexOf( this.map[hash], this.arr );
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delete this.map[hash];
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this.arr.splice( index, 1 );
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}
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};
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2012-09-26 19:10:37 +00:00
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/**
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* Remove all values.
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*/
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ve.OrderedHashSet.prototype.removeAll = function () {
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2012-09-28 19:17:04 +00:00
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var i = this.arr.length;
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while ( i-- ) {
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2012-09-26 19:10:37 +00:00
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this.remove( this.arr[i] );
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}
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};
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2012-08-24 02:06:36 +00:00
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/**
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* Remove all values in a given set from this set. Values that aren't in this set are ignored.
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* @param {ve.OrderedHashSet} set Set to remove from this set
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*/
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ve.OrderedHashSet.prototype.removeSet = function ( set ) {
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var i;
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for ( i = 0; i < set.arr.length; i++ ) {
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this.remove( set.arr[i] );
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}
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};
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/**
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* Remove all values that are not also in a given other set from this set.
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* @param {ve.OrderedHashSet} set Set to intersect with this set
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*/
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ve.OrderedHashSet.prototype.removeNotInSet = function ( set ) {
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var i;
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for ( i = this.arr.length - 1; i >= 0; i-- ) {
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if ( !set.contains( this.arr[i] ) ) {
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this.removeAt( i );
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}
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}
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};
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/**
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* Reverse this set.
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*
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* This returns a copy, the original set is not modified.
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*
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* @returns {ve.OrderedHashSet} Copy of this set with the order reversed.
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*/
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ve.OrderedHashSet.prototype.reversed = function () {
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var newSet = this.clone();
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newSet.arr.reverse();
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return newSet;
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};
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/**
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* Merge another set into this set.
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*
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* This returns a copy, the original set is not modified.
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*
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* @param {ve.OrderedHashSet} set Other set
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* @returns {ve.OrderedHashSet} Set containing all values in this set as well as all values in set
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*/
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ve.OrderedHashSet.prototype.mergeWith = function ( set ) {
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var newSet = this.clone();
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newSet.addSet( set );
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return newSet;
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};
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/**
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* Get the difference between this set and another set.
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*
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* @param {ve.OrderedHashSet} set Other set
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* @returns {ve.OrderedHashSet} New set containing all values that are in this set but not in set
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*/
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ve.OrderedHashSet.prototype.diffWith = function ( set ) {
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var newSet = this.clone();
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newSet.removeSet( set );
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return newSet;
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};
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/**
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* Get the intersection of this set with another set.
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*
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* @param {ve.OrderedHashSet} set Other set
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* @returns {ve.OrderedHashSet} New set containing all values that are both in this set and in set
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*/
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ve.OrderedHashSet.prototype.intersectWith = function ( set ) {
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var newSet = this.clone();
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newSet.removeNotInSet( set );
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return newSet;
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};
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